2. value: 11.11 points A small hair salon in Denver, Colorado, averages about 35

Question

2. value: 11.11 points A small hair salon in Denver, Colorado, averages about 35 customers on weekdays with a standard deviation of 11. It is safe to assume that the underlying distribution is normal. In an attempt to increase the number of weekday customers, the manager offers a $3 discount on 5 consecutive weekdays. She reports that her strategy has worked since the sample mean of customers during this 5 weekday period jumps to 45. Use Table 1 a. What is the probability to get a sample average of 45 or more customers if the manager had not offered the discount? (Round "z" value to 2 decimal places, and final answer to 4 decimal places.) Probability b. Do you feel confident that the manager's discount strategy has worked? O No, there is good chance (more than 5%) of getting 45 or more customers without the discount. O No, there is only a small chance (less than 5%) of getting 45 or more customers without the discount. O Yes, there is good chance (more than 5%) of getting 45 or more customers without the discount. O Yes, there is only a small chance (less than 5%) of getting 45 or more customers without the discount.

Explanation / Answer

a)

b)

yes there is only a small chance (less than 5%) of getting 45 or more customers without the discount

for normal distribution z score =(X-?)/? here mean=       ?= 35 std deviation   =?= 11.0000 sample size       =n= 5 std error=?x?=?/?n= 4.9193

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