Take a Test-Julian Mata-Google Chrome Secure https://www.mathxl.com/Student/Play

Question

Take a Test-Julian Mata-Google Chrome Secure https://www.mathxl.com/Student/Player Test.aspxPtestid-1766737748icenter SP18 STAT 251G-D05 Julian Mata&1 4/3/18 9:11 uiz: Quiz 7: Sections 9.1-9.4 Time Remaining: 00:17:11 Submit his Question: 1 pt 47 of 8 (6 complete) This Quiz: 10 pts poe Question Help In a survey of 1008 aduts, a poling agency asked, When you retre, do stated tal hey were worned ab???? having enough money to live cortetatly n retrement construct a 95% enfdenco wormed about having ernough money to live comfortably in retrement Cäck here to view the standard.normal distbution table (age 1) Cick here to.w the standarnd .normal distribution table (pege 2). Click here to yow the table of cntcalt-xalues you think you will have enough money to live comfortably or not Of the 1008 surveyed, 52 nterval for the proportion of adults who are Select the correct choice below and Sll in the answer boxes to complete your choioe (Use ascending order Round to theoe decimal places as needed ) OA. OB. ??. There s a 95% probably that the true proportion of woned auits is betweenland There is 95% condence that the proportion of womed adits is between 11 and 9?% of te populaton les n the mervd between and11 Click to select and enter your answeris)

Explanation / Answer

n = 1008

p = 526/1008 = 0.5218

z-value of 95% CI = 1.9600 .. using standard z table

SE = sqrt(p*(1-p)/n)

= sqrt(0.5218*(1-0.5218)/1008)

= 0.01573

ME = z*SE

= 1.96*0.01573

= 0.03084

Lower Limit = p - ME

= 0.5218 - 0.03084

= 0.49099

Upper Limit = p + ME

= 0.5218 + 0.03084

= 0.55266

95% CI (0.491 , 0.5527 )

There is a 95% probability that the true proportion of worried adusts is between 0.491 and 0.5527

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.