EditView History Bookmarks Window Help BUSA 21903 (Spring 2018) Homework: Homewo

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EditView History Bookmarks Window Help BUSA 21903 (Spring 2018) Homework: Homework of Section 6.1-6.3b Score: 0 of 1 pt 6 of 87 complete) MN Score: 59.17%, 4.73 of 8 pts 6.2.12-T Question Helip In 2008, the per capita consumption of soft drinks in Country A was reporied to be 19.44 gallons. Assume that the per capita consumption of soft drinks in Country Ais approximately normalily distributed, with a mean of 19.44 gallons and a standand deviation of 4 galions. Complete parts (a) through (d) below a. What is the probabiity that someone in Country A consumed more than 14 gallions of sot drinks in 20087 The probablity is 0.9131 (Round to four decimal places as needed) b. What is the probability that someone in Country A consumed bebween 7 and 9 gallons of sot drinks in 20087 The probability is (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer Check Answer Clear All This course (BUSA 21903 (Spring 2018 is based on Levine: Business Statistics A Finst Coue e Copyright 2018 Pearson Educatio

Explanation / Answer

Solution :- Given that ? = 19.44, ? = 4

a) P(X > 14) = P(Z > (X-?)/?)
= P(Z > (14-19.44)/4)
= 0.9131

b) P(7 < X < 9) = P((7-19.44)/4 < Z < (9-19.44)/4)
= P(-3.11 < Z < -2.61)
= 0.0036

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