A scientist conducted a hybridization experiment using peas with green pods and

Question

A scientist conducted a hybridization experiment using peas with green pods and yellow pods. He crossed peas in such a way that 25% (or 142) of the 568 offspring peas were expected to have yellow pods. Instead of getting 142 peas with yellow pods, he obtained 148 Assume that the rate of 25% is correct. a. Find the probability that among the 568 offspring peas, exactly 148 have yellow pods. b. Find the probability that among the 568 offspring peas, at least 148 have yellow pods. c. Which result is useful for determining whether the claimed rate of 25% is incorrect? (Part (a) or part (b)?) d. Is there strong evidence to suggest that the rate of 25% is incorrect? a. The probability that exactly 148 have yellow pods is (Round to four decimal places as needed.) b. The probability that at least 148 have yellow pods is (Round to four decimal places as needed.) C. V is useful for determining whether the claimed rate is incorrect. d. Is there strong evidence to suggest that the rate of 25% is incorrect? O Yes O No

Explanation / Answer

Solution:- Given values p = 0.25 , n = 568 ,

a) P(X = 148) = 0.0322

b) P(X >= 148) = 0.2951

c) part b is useful for determining whether the claimed rate is incorrect

d) option B. No

=> the probability part b is not small enough below 0.05

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