ailed White Results from a civil servant exam are shown in the table to the righ

Question

ailed White Results from a civil servant exam are shown in the table to the right. Is there sufficient evidence to support the claim that the results from the test are discriminatory? Use a 0.05 significance level. 15 Minority Determine the null and altemative hypotheses. OA. Ho: White and minority candidates have the same chance of passing the test O B. Ho: A white candidate is not more likely to pass the test than a minority candidate O C. Ho: White and minority candidates do not have the same chance of passing the test. O D. Ho: A white candidate is more likely to pass the test than a minority candidate H1: White and minority candidates do not have the same chance of passing the test. H1: A white candidate is more likely to pass the test than a minority candidate H1: White and minority candidates have the same chance of passing the test H1: A white candidate is not more likely to pass the test than a minority candidate Determine the test statistic. x2-O (Round to three decimal places as needed.) Determine the P-value of the test statistic P-value (Round to four decimal places as needed.) Is there sufficient evidence to support the claim that the results from the test are discriminatory 0 A. There is sufficient evidence to support the claim that the results are discriminatory. 0 B. There is not sufficient ovidence to reject the claim that a white candidate is more likely to pass the test than a minority candidate ° C. There is not sufficient evidence to support the claim that the results are discriminatory. 0 D. There is sufficient evidence to reject the claim that a white candidate is more likely to pass the test than a minority candidate

Explanation / Answer

Ans:

Null hypothesis and Alternative hypothesis:

Option A is correct.

Test statistic:

Chi square score=1.432

df=(2-1)*(2-1)=1

p-value=CHIDIST(1.432,1)=0.2314

As,p-value>0.05,we fail to reject null hypothesis.

There is not sufficient evidenec to support the claim that results are dicriminatory.

Option C is correct.

Observed(O) Passed failed Total white 14 15 29 Minority 11 22 33 Total= 25 37 62 Expected(E) Passed failed Total white 11.69 17.31 29 Minority 13.31 19.69 33 Total= 25 37 62 Chi square=(O-E)^2/E Passed failed Total white 0.455 0.307 0.762 Minority 0.400 0.270 0.670 Total= 0.855 0.578 1.432

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