Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

As part of the study on ongoing fright symptoms due to exposure to horror movies

ID: 3055359 • Letter: A

Question

As part of the study on ongoing fright symptoms due to exposure to horror movies at a young age, the following table was presented to describe the lasting impact these movies have had during bedtime and waking life:

(a) What percent of the students have lasting waking-life symptoms? (Round your answer to two decimal places.)
%

(b) What percent of the students have both waking-life and bedtime symptoms? (Round your answer to two decimal places.)
%

(c) Test whether there is an association between waking-life and bedtime symptoms. State the null and alternative hypotheses. (Use ? = 0.01.)

Null Hypothesis:

H0: Waking symptoms cause bedtime symptoms.H0: There is no relationship between waking and bedtime symptoms.     H0: There is a relationship between waking and bedtime symptoms.H0: Bedtime symptoms cause waking symptoms.


Alternative Hypothesis:

Ha: Waking symptoms cause bedtime symptoms.Ha: Bedtime symptoms cause waking symptoms.     Ha: There is a relationship between waking and bedtime symptoms.Ha: There is no relationship between waking and bedtime symptoms.


State the ?2 statistic and the P-value. (Round your answers for ?2 and the P-value to three decimal places.)


Conclusion:

We do not have enough evidence to conclude that there is a relationship.We have enough evidence to conclude that there is a relationship.

     Waking
symptoms Bedtime symptoms Yes      No Yes 36 32 No 32 19

Explanation / Answer

a)percent of the students have lasting waking-life symptoms =(68/119)*100 =57.14%

b) percent of the students have both waking-life and bedtime symptoms(36/119)*100 =30.25%

c)H0: There is no relationship between waking and bedtime symptoms.

Ha: There is a relationship between waking and bedtime symptoms

applying chi square test:

?2 =1.144

df =(row-1)*(column-1)=(2-1)*(2-1) =1

p value =0.2849

Conclusion:

We do not have enough evidence to conclude that there is a relationship.

Observed Oi Yes No Total Yes 36 32 68 No 32 19 51 Total 68 51 119 Expected Ei=?row*?column/?total Yes No Total Yes 38.8571 29.1429 68 No 29.1429 21.8571 51 Total 68 51 119 chi square =(Oi-Ei)2/Ei Yes No Total Yes 0.2101 0.2801 0.490 No 0.2801 0.3735 0.654 Total 0.490 0.654 1.144