> Cash osdepa 1774559 759 TOTALS 18830 14 78 27559 100180 3 PR .060 3/100 Submis

Question

> Cash osdepa 1774559 759 TOTALS 18830 14 78 27559 100180 3 PR .060 3/100 Submissions Used Your An article in the New England Journal of Medicine, reported about a study of smokers in California and Hawail. In one part of the report, the self reported ethnicity and smoking levels per day were given. Of the people Americans, 2,745 Native Hawailans, 12,831 Latinos, per day, there were 6,514 African Americans, 3,062 Native H smoking at most ten cigarettes per day, there were 9,886 African 8,378 Japanese Americans, and 7,650 Whites. Of the people smoking 11 to 20 cigarettes Americans, and 9,877 Whites. Of the awalans, 4,932 Latinos, 10,680 Japanese cigarettes per day, there were 1,671 African Americans, 1,419 Native Hawailans, 1,406 Latinos, 4,715 Japanese Americans, and 6,062 Whites. Of the people smoking at least 31 cigarettes per day, there were 759 African Americans, 788 Native Hawalians, 800 Latinos, 2,305 Japanese Americans, and 3,970 Whites Suppose that one person from the study is randomly selected. Find the probablity that person smoked 11 to 20 cigarettes per day. (Enter your probability as a fraction.) nd the column in the table that represents the event in question. How can the value of this column be used with the oumber of objects in the somple space to find the probability? 100180

Explanation / Answer

P(the person smoked 11 to 20 cigarettes per day) = Number of people who smoked 11-20 cigarettes per day / Total number people in the study

= (6514+3062+4932+10680+9877) / (9886+2745+12831+8378+7650 + 6514+3062+4932+10680+9877 + 1671+1419+1406+4715+6062 + 759+788+800+2305+3970)

= 35065 / 100450

= 7013/20090

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