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Table 1. Number of Cadillacs per Day Sold by Cadillac Salesman Gerald Date # Car

ID: 3056372 • Letter: T

Question

Table 1. Number of Cadillacs per Day Sold by Cadillac Salesman Gerald

Date

# Cars Sold

10/3/16

1

10/4/16

2

10/5/16

1

10/6/16

1

10/7/16

1

10/8/16

3

10/9/16

3

A) Use binomial probability distribution formula n/x=n!/x!(n-x)! to calculate the probability that Gerald would experience failure, failure, and then success on three attempted sales. B) What probability law did you use here?

Use this binomial probability function n/x=n!/x!(n-x)!to calculate the probabilities for the following: A) that Gerald will experience success on two out of four attempted sales, B) that Gerald will experience failure on four out of six attempted sales.

Consider the properties of a binomial experiment.

1. The experiment consists of a sequence of n identical trials.

2. Two outcomes are possible on each trial. We refer to one outcome as a success and the other outcome as a failure.

3. The probability of a success, denoted by p, does not change from trial to trial. Consequently, the probability of a failure, denoted by 1 p, does not change from trial to trial.

4. The trials are independent.

For this lab, we have assumed that these properties apply to the probability experiment with Gerald. For each property, is this an accurate assumption, or not? How so?

Table 1. Number of Cadillacs per Day Sold by Cadillac Salesman Gerald

Date

# Cars Sold

10/3/16

1

10/4/16

2

10/5/16

1

10/6/16

1

10/7/16

1

10/8/16

3

10/9/16

3

Explanation / Answer

Select 1 out of 3 sales which is a success- This can be done in C(3,1) ways which is equal to 3

Of the 3, 2 are failures

The probability of both success and failure is each equal to 0.5

So, required probability is C(3,1)*(0.5)^2*(0.5)= 0.375

I used the binomial distribution to get to the probability

The other two-

2 failures out of 4: So, required probability is C(4,2)*(0.5)^2*(0.5)^2= 6*0.5^4 = 0.375

4 failutres out of 6: So, required probability is C(6,2)*(0.5)^2*(0.5)^4= 15*0.5^6 = 0.234

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