5. Exercise 10.35 eBook Exercise 10 TABLE 10.6 EXAMINATION SCORES FOR 18 EMPLOYE

Question

5. Exercise 10.35 eBook Exercise 10 TABLE 10.6 EXAMINATION SCORES FOR 18 EMPLOYEES Plant 1 Atlanta 85 75 82 76 71 85 Plant 2 Dallas 71 75 73 74 69 82 Plant 3 Seattle 59 64 62 69 75 67 Sample mean Sample variance Sample standard deviation 79 34 5.83 74 20 4.47 32 5.66 Set up the ANOVA table Mean p-value (to 3 decimals) Source of Sum of Degrees of Square (to 2 decimals) Variation Squares Freedom Treatments Error Total Test for any significant difference in the mean examination score for the three plants. Use a = .05 - Select vour answer that the means for the three plants are equal

Explanation / Answer

From the statistical software output, the ANOVA table will be:

ANOVA table

Reject Ho that the means for the three plants are equal.

Source SS Df MS F-Stat P-value Treatment 516 2 258 9 0.003 Error 430 15 28.67 Total 946 17

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