6. Area under the normal distribution A Aa The following figure shows the normal

Question

6. Area under the normal distribution A Aa The following figure shows the normal distribution with the proportion of the area under the normal curve contained within one, two, and three standard deviations of the mean. The last proportion on each side, 0.13%, depicts the remaining area under the arve. Specifically, 0.13% of the area under the standard normal distribution is located above z-score values greater than the mean (u) plus three standard deviations (+30). Also, because the normal distribution is symmetrical, 0.13% of the area under the standard normal distribution is located below z-score values less than the mean (u) minus three standard deviations (-30). 34.13% 34.13% 13.59% 13.59% 2.15% 2.15% 0.13% 0.13% Use the figure to help you answer the following questions The National Assessment of Educational Progress (NAEP) is a nationwide assessment of students' proficiency in nine subjects: mathematics, reading, writing, science, the arts, civics, economics, geography, and U.S. history. The main NAEP assessments are conducted annually on samples of students from grades 4, 8, and 12. In 2000, the science scores for female students had a mean of 146 with a standard deviation of 35. Assume that these scores are normally distributed with the given mean and standard deviation. below the mean, while a score of 216 is A score of 76 is above the mean. This means that the percentage of female students with scores between 76 and 216 is A score of 251 above the mean. As a result, the percentage of female students with

Explanation / Answer

Answer to the question is as follows:

X = 76
Z = X-Mu /Sigma = (76-146)/35 = -2

X=216
Z = X-Mu/Sigma = (216-146)/35 = 2

A score of 76 is 2 below the mean, while a score of 216 is 2 deviations above mean.

This means that the percentage of female students with scores between 76 and 216 is 95%

A score of 251 is 251-216/35 = 1 above the mean. As a result , percentage of female students with scores below 251 is .5+.3413 = .8414 or 84.13%

You can infer that 84.13% of the female students have scores above 216-35 = 181

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