4. 1.5 points My Notes An airline, believing that 4% of passengers fail to show

Question

4. 1.5 points My Notes An airline, believing that 4% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppose that for a particular flight involving a jumbo-jet with 267 seats, the airline sells 276 tickets. Question 1. What is the expected number of ticket holders that will fail to show for the flight? (Use 2 decimal place in your answer.) Question 2. What is the probability that the airline will not have enough seats for all the ticket holders who show for the flight? (Use 3 decimal places.)

Explanation / Answer

Ans:

Probability of show up for flight=1-0.04=0.96

Let x be the number of passengers who show up for flight.

Then,x has binomial distribution with n=276,p=0.96

a)Expected number of passengers who fail to show up for flight=np=276*(1-0.96)=11.04

b)P(flight is overbooked)=P(x>267)=1-P(x<=267)=1-binomcdf(267,276,0.96,true)=0.223

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