Question 3 Suppose men\'s height is normally distributed with mean 69 in. and st
ID: 3057362 • Letter: Q
Question
Question 3
Suppose men's height is normally distributed with mean 69 in. and standard deviation 3 in. Women's height is normally distributed with mean 64 in. and standard deviation 2 in.
John is 73 in. tall and Mary is 62 in.
Question 3 options:
A. _____
If JANE is considered with a height of 67 in., who is MORE EXTREME relative to their population John or Jane?
B. _____
Who is MORE EXTREME relative to their gender populations John or Mary?
C. _____
Who was closest to their population's 50th percentile John or Mary?
What is John's z-score?
E. _____
What is Mary's z-score?
Note: Below choices may NOT all be used as matches.
Mary
-1.00
1.33
1.00
No answer is correct.
John and Mary have the same position in their populations.
Jane
John
.
A. _____
If JANE is considered with a height of 67 in., who is MORE EXTREME relative to their population John or Jane?
B. _____
Who is MORE EXTREME relative to their gender populations John or Mary?
C. _____
Who was closest to their population's 50th percentile John or Mary?
D. _____What is John's z-score?
E. _____
What is Mary's z-score?
1.Note: Below choices may NOT all be used as matches.
2.Mary
3.-1.00
4.1.33
5.1.00
6.No answer is correct.
7.John and Mary have the same position in their populations.
8.Jane
9.John
Explanation / Answer
I think John is male and Mary and Jale are female..
we find z-score for them and z=(x-mean)/sd
for John, z=(73-69)/3=1.33
for mary, z=(62-64)/2=-1
for Jane, z=(67-64)/2=1.5
(A)Jane, as Jane z-score is more than John
(B)John, as absolute z-score is more for John
(C) mary, because mary z score= -1 is near to 0 than John
(D)John, z=(73-69)/3=1.33
(E)-1
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