n=48 A product\'s service life is distributed normally with a mean of 12 years a
ID: 3059030 • Letter: N
Question
n=48
A product's service life is distributed normally with a mean of 12 years and n months and a standard deviation of 18 months. Example: Mean = 12 years + n months-144 months + 45 months = 189 months Use your n (the summation of all digits of your ID number) to answer the following questions: Roun d your non-integer answers to four decimal places. What is the probability that this product will perform reliably for 12.5 years? A. B. What is the probability that this product will fail due to wear out within 16 years? Hints: Make sure the mean, standard deviation, and expected product life are represented by the same time interval/scale (either months or years).Explanation / Answer
n=48
A product's service life is distributed normally with a mean of 12 years and n months and a standard deviation of 18 months. Example: Mean = 12 years + n months-144 months + 45 months = 189 months Use your n (the summation of all digits of your ID number) to answer the following questions: Roun d your non-integer answers to four decimal places. What is the probability that this product will perform reliably for 12.5 years? A. B. What is the probability that this product will fail due to wear out within 16 years? Hints: Make sure the mean, standard deviation, and expected product life are represented by the same time interval/scale (either months or years).Related Questions
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