0 ngor ngage covstatic/nb/uVindex html? bld-748 173&nt; Nod Id=283043058 MINDTAP
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0 ngor ngage covstatic/nb/uVindex html? bld-748 173&nt; Nod Id=283043058 MINDTAP Complete: Chapter 7 Problem Set Due Todey at 1159 PM CST Let's examine the mean of the numbers 1, 2, 3,4, 5, 5, 7, 8, 9, and 10 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roil a tan-sided dia two tirmes (or equivalently, roll two tan-sided dioe one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3,4,5 6, 7, 8, 9, and 10. The trus mean (u) of the numbers 1, 2, 3,4, 5, 6, 7, 8, 9, and 10 is and the true standard deviation () is The number of possible different samples (each of size n - 2) is the number of possibilites on the first roll (10) times the number of possibilities on the second roll (also 10), or 10(10)-100. If you collected all of these possible samples, the mean of your sampling distribution of means (pa) would equal your sampling distribution of means (that is, the standard error or aw) would be , and the standard deviation of The following chart shows the sampling distribution of the mean (M) for your experiment. Suppose you do this experiment once (that is, you roll the die two times) Use the chart to determine the probability that the mean of your two rolis is equal to the true mean, or P(M-p),iThe probability that the mean of your two rolls is greater than or equal to 9.5, or P(M 2 9.5), s 12 10 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 9D 95 100 Type here to searchExplanation / Answer
0 ngor ngage covstatic/nb/uVindex html? bld-748 173&nt; Nod Id=283043058 MINDTAP Complete: Chapter 7 Problem Set Due Todey at 1159 PM CST Let's examine the mean of the numbers 1, 2, 3,4, 5, 5, 7, 8, 9, and 10 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roil a tan-sided dia two tirmes (or equivalently, roll two tan-sided dioe one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3,4,5 6, 7, 8, 9, and 10. The trus mean (u) of the numbers 1, 2, 3,4, 5, 6, 7, 8, 9, and 10 is and the true standard deviation () is The number of possible different samples (each of size n - 2) is the number of possibilites on the first roll (10) times the number of possibilities on the second roll (also 10), or 10(10)-100. If you collected all of these possible samples, the mean of your sampling distribution of means (pa) would equal your sampling distribution of means (that is, the standard error or aw) would be , and the standard deviation of The following chart shows the sampling distribution of the mean (M) for your experiment. Suppose you do this experiment once (that is, you roll the die two times) Use the chart to determine the probability that the mean of your two rolis is equal to the true mean, or P(M-p),iThe probability that the mean of your two rolls is greater than or equal to 9.5, or P(M 2 9.5), s 12 10 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 9D 95 100 Type here to search
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