In an article in the Journal of Advertising, Weinberger and Spotts compare the u

Question

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor. (a) Suppose that a random sample of 382 television ads in the United Kingdom reveals that 140 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor. (Round your answers to 3 decimal places.) 1formula86.mml = The 95 percent confidence interval is [,]. (b) Suppose a random sample of 492 television ads in the United States reveals that 119 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor. (Round your answers to 3 decimal places.) 1formula86.mml = The 95 percent confidence interval is [,]. (c) Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? , the U.K. 95 percent confidence interval is the maximum value in the confidence interval for the U.S.

Explanation / Answer

a)

b)

c)Yes ;as

the U.K. 95 percent confidence interval lower limit is higher than the the maximum value in the confidence interval for the U.S

                                                                                           x                    =   140 sample size n                    = 382 point estimate p x/n= 0.3665 std error       =Se            =(p*(1-p)/n) = 0.0247 for 95 % CI value of z= 1.9600 margin of error E=z*std error                            = 0.048 lower confidence bound=sample proportion-margin of error 0.318 Upper confidence bound=sample proportion+margin of error 0.415

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