Thank you. Most major airlines allow passengers to carry two pieces of luggage (

Question

Thank you. Most major airlines allow passengers to carry two pieces of luggage (of a certain maximum size) onto the plane. However, their studies show that the more carry-on baggage passengers have, the longer it takes to unload passenger. Before doing so, it decided to collect some data. Specifically, a random sample of 1,000 passengers was selected. The passengers were observed, and the number of bags carried on the plane was noted. Out of the 1,000 passengers, 369 had more than one bag Complete parts a through d below One regio Click the icon to view a table of critical values for commonly used confidence levels. a Based on this sample, develop and interpret a 90% confidence interval estimate for the proportion of the traveling population that would have been impacted had the one-bag limit been in effect Determine the confidence interval 0 344 0 394 Round to three decimal places as needed. Use ascending order) Which statement below correctly interprets the confidence interval? A. There is 90% confidence that the population proportion of passengers with more than one carry-on bag is n the interval O B. There is a 0 90 probability that the sample proportion of passengers with more than one carry-on bag is in the interval. () C. Of all the possible population proportions of passengers with more than one carry-on bag 90% are in the interval 0 D. There is a 0 90 probability that the population proportion of passengers with more than one carry-on bag is in the interval

Explanation / Answer

a)

Test and CI for One Proportion

Sample    X     N Sample p         90% CI
1       369 1000 0.369000 (0.343901, 0.394099)

Using the normal approximation.

b)

total passenger = 550

hence interval estimate =

(189.145,216.755)

=(189,217)

c)

Test and CI for One Proportion

Sample    X    N Sample p         90% CI
1       293 653 0.448698 (0.416684, 0.480713)

Using the normal approximation.

d)

minimum sample size n = z^2 * p *q /e^2

for 90% z = 1.645

e = 0.03 , p = 0.10 ,q = 0.9

n = 1.645^2 * 0.1*0.9/0.03^2= 270.6025

271 passenger are needed (try 270 if wrong)

0.3439 189.145 0.3941 216.755

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