? > C ? ? www.saplínglearning.com/ibiscms/mod/ibis/view.php?id=5908382 Digital R

Question

? > C ? ? www.saplínglearning.com/ibiscms/mod/ibis/view.php?id=5908382 Digital Resources forSupreme New Sapling Learning macmillan learning Sapling LearningMcNeese State University - PHYS 211 - Summer18- STINNETTActivities and Due Dates HW: Dynamics of Rotational Motion My Assignment 07/23/2018 10:00 PM , 30/100?7/21/201 8 04:13 PM Gradeboo Attempts Score -Print Calculator-Periodic Table 100 Question 10 of 10 100 Sapling Learning Map 100 A 1840 kg car has just passed a diner The closest the car came to the diner was R 32.5 m, but the car has driven another x 26.7 m in the 2.45 s elapsed since then. If the car travels at constant speed, what is the current magnitude of the angular momentum of the car about the diner? 4 Number kg·m"/s 8 10 0 Previous Check Answer Next Exit Hint

Explanation / Answer

Given,

Mass, m = 1840 kg

Distance R = 32.5 m

Time t = 2.45 sec

speed of car = 26.7/2.45 = 10.90 m/s

Angular momentum = m v r = 1840 x 10.90 x 32.5 = 651697.96 kg m^2/s  (Ans)

Comment in case any doubt please rate my answer ....

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.