A lead inspector at ElectroTech, an electronics assembly shop, wants to convince
ID: 3061436 • Letter: A
Question
A lead inspector at ElectroTech, an electronics assembly shop, wants to convince management that it takes longer, on a per-component basis, to inspect large devices with many components than it does to inspect small devices because it is difficult to keep track of which components have already been inspected. To prove her point, she has collected data from the last 25 devices. The data are shown in the accompanying table.
Number of Components
on Device
http://lectures.mhhe.com/connect/0078020557/Ch16/Static/Ch16_Q10_Data_File.xlsx
a.
A scatterplot of the above data is shown below. Does the lead inspector’s claim seem credible?
B-1 needs to be 4 digits please
Number of Components
on Device
Inspection Time (seconds) 32 84 13 49 9 30 17 60 15 51 11 41 24 71 42 99 7 22 12 42 19 63 8 26 30 80 12 48 10 31 19 62 16 52 19 60 25 72 44 102 16 59 13 44 21 67 12 46 23 70 * - 86% (40) Mon 11:00 AM 9 0 i Firefox File Edit View History Bookmarks Tools Window Help Ch. 16 HW C Chegg Study | Guided Solution x + -) C 0 ezto.mheducation.com/hm.tpx e *** V * Q Search lille S 0 = Time (sec) 8 8 8 * & - ODOS A B D P - E O Q8 - TE FI Number of components O Yes O No b-1. Estimate the linear, quadratic, and cubic regression models. Report the Adjusted R for each model. (Round your answers to 4 decimal places.) Linear model Quadratic model Cubic model Adjusted R2 0.9106 0.9572 0.9614 b-2. Which model has the best fit?Explanation / Answer
From the scatter plot, we can conclude that increased the number of components on Device increased the Inspection Time and decrease the number of components on Device decreased the Inspection Time. So, the lead inspection's seem is credible.
Ans: Yes.
b-2. The largest R^2 value is 0.9614 with corresponding to Cubic model. Hence, the best model fit is 'cubic model'.
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