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ng Statistes Actv Mind Tapreengage Lea × e search Textbook Solutions I | New tab nuindex.html?nbld-740535&nbNodeld;:279600242&deploymentid;=488 1078834230286703255 1 1 9&elSBN-978; 12858680 Activity DT Video Excel Online Structured Activity: Interval Estimation for the Population Mean with Unknown Sample data from a normal population are located in the Microsoft Excel Online file below Use the data to answer the following questions for the unknown case. a. The point estimate of the population mean is (to 2 decimals) b. The standard deviation is (to 2 decimals) c. The margin of error is (to 1 decimal) dThe 95% confidence interval is (to 1 decimal) to Back 0 ere to search

Explanation / Answer

a) The point estimate of Population Mean is Sample Mean

Sample Mean = (3+10+....+15+15)/8 = 11.87

b) Sample Variance = { (3-11.87)^2 + (10-11.87)^2 + ...... + (15-11.87)^2 + (15-11.87)^2 }/ (8-1) = 4.97^2

Sample Standard Deviation = 4.97

d) 95% CI = Sample Statistic +- Margin of Error

At 95% CI, Z = 1.96

CI = 11.87 -+ 1.96*4.97/sqrt(8)

= 11.87 -+ 3.44

= {8.43, 15.31 }

c) Margin of Error = 3.44

Hope this helps and Please don't forget to rate the answer :)

Sample Data 3 10 11 14 19 8 15 15

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