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Do e Secure https://www.mathxl.com/Student/ Homework.aspx?homeworkId-470386628&questionId;=31&I; BBA303-SPRING 2018 3/15/18 12:34 AM Homework: Chapter 2 Score: 0 of 1 pt 31of40(33 complete) Hw Score: 75.28%, 30.11 of 40 2.4.36 36, the mean duration of a geysers eruptions is 3.08 minutes and the standard deviation is 0.66 minutes. Using Chebychev's Theorem. determine at least how many of the eruptions lasted between 1.1 and 5.06 minutes. At least of the eruptions lasted between 1.1 and 5.06 minutes. (Simplify your answer.) 11.. 1 1.1 |Ja|:/ì | 1. I cu) | More in the box and thenrclick Check Answer Clear All

Explanation / Answer

Solution:

We have mean 3.08, and standard deviation = 0.66. The interval we consider is the mean ± 2
Using Chebychev's inequality, we get that the probability that the variable is outside of this interval cannot exceed 1 / (2^2) = 1/4. So at least 75% of the eruptions lasted between 1.1 and 5.06 minutes.

So at least 0.75* 36 = 27 eruptions lasted between 1.1 and 5.06 minutes.

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