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Need help especially with 17,19,21,23.will appreaciate it if u do extra CHAPTER

ID: 3062189 • Letter: N

Question

Need help especially with 17,19,21,23.will appreaciate it if u do extra

CHAPTER 3 Probability and you had to select the correct combination of all six numbers to win prize. For a $1 bet, you selected two different six-number combinations. ve rnd 24. Genes color not select a single six-number combination: you had to select two.) a. If you placed a SI bet and selected two different six-number was the probability of winning the grand prize? has a b. Was it unusual to win the grand prize? 17. Probability of a Birthday a. Li a. If a person is randomly selected, find the probability that his or her birthday is tober 18, which is National Statistics Day in Japan. Ignore leap years. b. If a person is randomly selected, find the probability that his or her birthday is in October. Ignore leap years c. If a person is randomly selected, find the probability that he or she was born on a 25. Kent day of the week that ends with the letter y 18. Probability of Brand Recognition a. In a study of brand recognition, 831 consumers knew of Campbell's Soup, and 18 did not (based on data from Total Research Corporation). Use these results to esti mate the probability that a randomly selected consumer will recognize Campbell's d. I Soup 1 Estimate the probability that a randomly selected adult American consumer will nize the brand name of McDonald's, most notable as a fast-food restaoran 26. Fin and out chain. c. Estimate the probability that a randomly selected adult American consumer will recognize the brand name of Veeco Instruments, a manufacturer of microelectronic products. b. 19. Fruitcake Survey In a Bruskin-Goldring Research poll, respondents were asked how a fruitcake should be used. One hundred thirty-two respondents indicated that i d. should be used for a doorstop, and 880 other respondents cited other uses, birdfeed, landfill, and a gift. If one of these respondents is randomly selected, what is incloding the probability of getting someone who would use the fruitcake as a doorstop? 20. Probability of a Car Crash Among 400 randomly selected drivers in the 20-24 bracket, 136 were in a car accident during the last year (based on data from the Na- tional Safety Council). If a driver in that age bracket is randomly selected, what is the approximate probability that he or she will be in a car accident during the next year? Is the resulting value high enough to be of concern to those in the 20-24 age bracke? Probability of Winning Solitaire Refer to Data Set 27 in Appendix B and assume that the same Microsoft solitaire game is played. a. Estimate the probability of winning when a game is played. b. Estimate the probability of running the whole deck by winning $208. 3-2 21. 27. In ti Probability of an Adverse Drug Reaction When the drug Viagra was clinically tested, 117 patients reported headaches and 617 did not (based on data from Pfizer, Inc.). Use this sample to estimate the probability that a Viagra user will experience a headache. Is the probability high enough to be of concern to Viagra users? 22. 28. D 23. Gender of Children: Constructing Sample Space Section 3-2 included a table sum- marizing the gender outcomes for a couple planning to have three children. a. Construct a similar table for a couple planning to have two children. b. Assuming that the outcomes listed in part (a) are equally likely, find the probability 29. 1 of getting two girls. c. Find the probability of getting exactly one child of each gender

Explanation / Answer

Solution:

   17)

      Part a) We have to find the probability that a randomly selected person has his or her birthday is October 18 , which is a National statistics daya in Japan. we have to ignore leap year.
So for non leap year , there are total 365 days.

A person can born on any day of the year with equal chance for each day.

So P(a person born on any day of the year ) = 1 / 365

Thus

P( a person born on day October 18 of the year ) = 1 / 365

P( a person born on day October 18 of the year ) = 0.000274

Part b) we have to find Probability of a randomly selected person has his or her birthday in October.

Month october has 31 days , so person whose birthday in octber has 31 possitbilities.

Thus

P( a person has birthday in October) = Number of days in October / Total days in year

P( a person has birthday in October) = 31 / 365

P( a person has birthday in October) = 0.08493

Part c) We have to find the probability that a randomly selected person has his or her birthday on the day of the week that ends with letter y

All the days of the week end with letter y

That means all the days of the year has days with letter ending with ' y '.

Thus there are 365 possibilities.

Thus

P( a person has his or her birthday on the day of the week that ends with letter y) = 365 / 365

P(a person has his or her birthday on the day of the week that ends with letter y ) = 1

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