A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 pu

Question

A jar of 150 jelly beans contains 22 red jelly beans, 38 yellow, 20 green, 28 purple, 26 blue, and the rest are orange.

Let   B = the event of getting a blue jelly bean

Let G = the event of getting a green jelly bean.

Let O = the event of getting an orange jelly bean.

Let P = the event of getting a purple jelly bean.

Let R = the event of getting a red jelly bean.

Let Y = the event of getting a yellow jelly bean.

What is the probability of drawing a red jelly bean in the first draw WITHOUT replacing the red jelly bean, then choosing a blue jelly bean in the second draw?

Use 4 decimal places for this problem. Do not round your answers for intermediate steps, only for the final answer.

Explanation / Answer

P(R in the first draw) = 22/150

If the first one is not replaced, there are 149 beans remaining in the jar, of which 26 are blue

P(B in second draw) = 26/149

P(red first and blue second) = 22/150 x 26/149

= 0.0256

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