Given a standardized normal distribution (with a mean of 0 and a standard deviat

Answer to the question is as follows: a. P(-1.59

ID: 3062653 • Letter: G

Question

Given a standardized normal distribution (with a mean of 0 and a standard deviation of 1), complete parts (a) through (d) below.

a. What is the probability that Z is between -1.59 and 1.84?

The probability that Z is between 1.59 and 1.84 is

(Round to four decimal places as needed.

2. A set of final examination grades in an introductory statistics course is normally distributed, with a mean of 79

and a standard deviation of 88.

Complete parts (a) through (d).

What is the probability that a student scored below 91

on this exam?

The probability that a student scored below 91 IS

(Round to four decimal places as needed.

Answer to the question is as follows:

P(-1.59<Z<1.84)

= P(Z<=1.84) - P(Z<=-1.59)

= .9671-.0559

= 0.9112

We have been given params of normal distribution:

Mean = 79

Stdev = 88

We will use these to normalize the distribution:

P(X<91)

= P(Z< 91-79/88) [refer the Z tables to solve this]

= 0.5542

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