The following table Wil Samipie Ull adult children financial assistance to buy a

Question

The following table Wil Samipie Ull adult children financial assistance to buy a car and to pay rent. Pay Rent Yes 56 14 70 Buy a Car Yes No total 108 Ne 52 78 130 totals 200 LetC the event of financial assistance to buy a car R = the event of financial assistance to pay rent Develop a joint probability table. a. Pay Rent Buy a Car Yes b. Use the joint probability table created in (a) to compute the conditional probability P(CIR)( in other words If parents provided financial assistance with paying rent, what is the probability that the parents assisted with buying a car). ve a sample space S (1, 52, 51,54, 5, s, ), where si, $2...,s." dlenote the sample points. The robability assignments apply: P()-0.05, P(s)-0.15, P(s)-0.15, P(sa)-0.2, P(ss)-0.1, P(so)-0.1, 2. Suppose that we ha La 025

Explanation / Answer

Question 1

(a) Here we will make joint probability table by using the formula

f(C,R) = Total number of specific category people/ Total number of people

So,

for f( C = Buy a Car and R = Pay Rent) = Total number of such people /Total number of people = 56/200

similarly,

f(C = Buy a Car and R = dont pay rant) = 78/200

so we will make probability distribution in such way

here

we have to Find P(C l R) =Pr( people whose parents assisted in both paying rent and car)/Pr( who assisted in paying rents) = 0.28/0.35 = 0.8

Question 2

here A = {s1,s4,s6} , B = {s2,s4,s7}

Here P(B) = P(S2) + P(s4) + P(s7) = 0.15 + 0.20 + 0.25 = 0.60 )

(B) P(A B) ; Here as we see that s4 is common among both sets

so P(A B) = P(s4) = 0.2

(C) Here A and B are not mutually exclusive as P(A B) 0

(D) P(Bc) = 1 - P(B) = 1 - 0.6 = 0.4

Pay Rent Buy A Car Yes No Total Yes 0.28 0.26 0.54 No 0.07 0.39 0.46 Total 0.35 0.65 1

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