oluwaseun onaolapo& 3/17/18 10:22 PM MATH 331.W01 SPRING2018 (1) Homework: Hw #
ID: 3063250 • Letter: O
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oluwaseun onaolapo& 3/17/18 10:22 PM MATH 331.W01 SPRING2018 (1) Homework: Hw # 3 Score: 0 of 1 pt 5.3.40 Save 6 of 22 (13 complete) HW Score: 53.03%, I 1.67 of 22 pts Question Help It is estimated that 4500 of the 15,000 voting residents of a town are against a new sales tax. If 14 el gible voters are selected at random and asked their opinion, what is the probability that at most 7 favor the new tax? Click here to view page 1 of the table of binomial probability sums. Click here to view page 2 of the table of binomial probability sums. The probability that at most 7 favor the new tax is Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer. All parts showing Clear All Check AnswerExplanation / Answer
P(against new tax) = 4500 / 15000 = 0.3
P(in favour) = 1 - 0.3 = 0.7
n = 14
This is a binomial distribution.
P(X = x) = 14Cx * 0.7x * (1 - 0.7)14-x
P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)
= 14C0 * 0.70 * 0.314 + 14C1 * 0.71 * 0.313 + 14C2 * 0.72 * 0.312 + 14C3 * 0.73 * 0.311 + 14C4 * 0.74 * 0.310 + 14C5 * 0.75 * 0.39 + 14C6 * 0.76 * 0.38 + 14C7 * 0.77 * 0.37
= 0.0933 (ans)
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