2. A Gallu p survey done in a small town found in the early 2000s that 46% of wo

Question

2. A Gallu p survey done in a small town found in the early 2000s that 46% of women and 37 probabilities. 1% of men experience daily pain. Compute the following a. What is the probability that a woman will not experience daily pain? b. What is the probability randomly selecting someone from the city who is a woman who experiences daily pain or a man who experiences daily pain? c. What is the probability of selecting a woman who experiences daily pain and a man who does not experience daily pain? (with replacement)

Explanation / Answer

Ans:

Given that

P(woman have pain)=0.46

P(man have pain)=0.37

Both events are independent and mutually exclusive

a)P(not woman have pain)=1-0.46=0.54

b)P(woman or man have pain)=P(woman have pain)+P(man have pain)

=0.46+0.37=0.83

c)P(woman have pain and man not have pain)=P(woman have pain)*(man not have pain)

=0.46*(1-0.37)

=0.46*0.63=0.2898

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