Secure https://www.mathxl.com/Student xtestld-1778217658centerwinsyes STCC Stats
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Secure https://www.mathxl.com/Student xtestld-1778217658centerwinsyes STCC Stats Nights Spring 2018 lynn marnen a 1 3/18/18 6 est: Exam Chapter 5 Time Remaining: 00:51:11 Sut his Question: 1 pt 18 of 29 (15 complete This Test: 29 pts in a survey of women in a certain country (ages 20-29), the mean height was 64 8·nches with a standard deviation of 2 88 inches Answer the following quest about the specified normal distribution (a) What height represents the 95th percentile? (b) What height represents the first quartile? (a) The height that represents the 96th percentile is inches (Round to two decimal places as needed) (b) The height that reprosents the first quartile isinches (Round to two decimal places as needed.) Enter your answer in each of the answer boxesExplanation / Answer
a) for 95th percentile ; z score =1.6449
hence corresponding height =mean +z*Std deviation =69.52 ( please try 69.54 if this does not work due to rounding)
b)
for 25th percentile ; z score =-0.6745
hence corresponding height =mean +z*Std deviation =62.86 ( please try 62.87 if this does not work due to rounding)
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