Question 1: Assume the commute time between lectures (travel time between two cl

Question

Question 1: Assume the commute time between lectures (travel time between two classes) for Penn State University Park students is a random variable that follows the normal distribution with a mean of 10.3 minutes with a standard deviation of 4.8 minutes. Use this information and answer questions 1a to 1f Question 1 5 pts Question 1a: You wish to calculate the probability that the commute time is more than 15.34 minutes. What is the corresponding z value you would look up in the standard normal table to answer this question? Question 2 Question 1b What is the probability that the commute time is more than 15.34 minutes? Question3 5 pts Question 1c The university realized that it is important to ensure that the commute time is less than 15 minutes for majority of students, what would be the targeted average commute time so that 97.5% of the students will spend less than 15 minutes traveling between classes assuming the standard deviation remains 4.8 minutes? (use 2 decimal places) Question 4 4 pts Question 1d: Which one of the following would be the new probability density function for the question 1c assuming the original pdf is A (the blue solid line)? O Line A O Line B O Line C O Line D Line E O None of the above Question 5 5 pts Question 1e: The university realized that it is important to ensure that the commute time is less than 15 minutes for the majority of students. What would be the targeted standard deviation of commute time so that 97.5% of the students will spend less than 15 minutes traveling between classes assuming the average commuting time is 10.3 minutes? (use 3 decimal places) Question 6 Question 1f: Which one of the following would be the new probability density function for the question 1e assuming the original pdf is A (the blue solid line)? O Line A Line O Line C Line D O Line E O None of the above

Explanation / Answer

1) z score = (15.34-10.3)/4.8 = 1.05

2) P(z>1.05)

Use Excel function

1-NORMSDIST(1.05)

= 0.1469

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.