Flowchart for Hypothesis scanned Document D Microsoft Word-FinalExar ?attempt-64
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Flowchart for Hypothesis scanned Document D Microsoft Word-FinalExar ?attempt-6429148page 3 From extensive records, t s known that the duration of treating a disease by a standard therapy has a mean of 15 days. t is claimed that a new therapy can reduce the treatment time. to test this claim, the new therapy is tried on 70 patients, and from the data of theirtimes to recovery, the sample mean and standard deviation are found to be 14.6 and 3.0 days respectively a) State the null and alternative hypotheses for testing the claim. 01. Ho: usl5 vs Ha: > 15 2. Ho: -15 vs Ha: * 15 o 3.Ho: 2 1 5 vs Ha:Explanation / Answer
Duration of treating a disease by a new therapy has a mean of 14.6 days.
Here our aim is to test claim whether that a new therapy can reduce the treatment time
Hence the null and alternative hypothesis of testing claims as:
H0 : µ 15 vs H1 : µ < 15 (option 3)
2.Formula of test statistics is
One-sample z-test (Option a)
z= (xbar-mu)/(sigma/sqrt(n))
3.Calculate the value of test statistics
Here µ=15
Value of test statistics Z= 1.12
4.Now to perform the hypothesis test at the 2.5% level of significance:
H0 15 vs H1 : µ < 15
Test statistic (Z) = 1.12
Rejection region: z < 1.96
Conclusion: Since the test statistic = 1.12 is not in the Rejection region, we do not reject H0 at = .025.
There is insufficient evidence to indicate that the new therapy can reduce the treatment time.
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