| Question Heip ATV show. Lindsay and Tob as, rece ey had a share of 10. mean gh
ID: 3064192 • Letter: #
Question
| Question Heip ATV show. Lindsay and Tob as, rece ey had a share of 10. mean ght am ngthe TV sets nusa 10% woo b plot survey begins with 20 households having TV sets in use at the time ef a Lindsay and Tobias broadcast edtothat show Assume that an adver er wan tove my that 10% share vak t by 6 ndefgRuown sur, and a. Find the probability that none of the households arne tuned to Lindbay and Tobias (Round to three decimal places as needed) b. Find the probaiblity that at least one hounehold is tuned to Lindsay and Tobins Round to three decimal places as needed) c. Find the probability that at mest one household is tuned to Lindsay and Tobias Round to three decimal places as needed ) d.1t mast one household istmed to Lndsay and Tobas, doesitappear that he 10% share value is wrong? Why or why not? OA. . 0 0 D. No, because wit, a 10% rate, te pobabey eat meat ane household is greater than 0 05 No, because wea10% fn. t, probability of at most one household is less than 0 05. Yes because with a 10% rate, the probabity of at most one household ls less than 0 05 Yes, because with 10% rate the probabley o, at most one household is reater that OS Clck to select your answerts)Explanation / Answer
Solution:
Given that n = 20 and p = 0.10
Using binomial distribution formula,
P (X = x) = 20Cx (0.10)^x (0.90)^20-x
a. P (X = 0) = 20C0 (0.10)^0 (0.90)^20
P (X = 0) = 0.1216
b. P (X 1) = 1 - P (X < 1)
= 1 - P (X = 0)
= 1 - 20C0 (0.10)^0 (0.90)^20
= 1 - 0.1216
= 0.8784
c. P (X 1) = P (X = 0) + P (X = 1)
= 20C0 (0.10)^0 (0.90)^20 + 20C1 (0.10)^1 (0.90)^19
= 0.1216 + 0.2702
= 0.392
d. No, because with a 10% rate, the probability of at most one household is greater than 0.05
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