Use detailed steps please. I’m a little confused Use the following contingency t
ID: 3065005 • Letter: U
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Use detailed steps please. I’m a little confused Use the following contingency table to determine whether variable I is independent of variable 2. Let -0.05 4. Variable2 23 17 Total 12 21 20 18 Variable l 8 Total Freq: Count Contingency Table Variable 1 By Variable 2 Count Expected Z Total Cell Chit223 21 12 11.0365 20.8467 24.1168 0.0841 0 2224 04028 17 8.88861 16.7518 19.3796 18 7.09489 13.4015 15.5036 0.0013 0.4303 04020 Total275159 137 Tests DF LogLike RSquare (U) 0.0058 4 0.83571979 137 Test Likelihood Ratio Pearson ChiSquare Prob>ChiSq 0.7959 0.7995 1,671 1.652 c. Use the chi-square value to test the independence d. Use the p-value to test the independenceExplanation / Answer
c) The calculated value of Chi square is 1.652
The critical value of chi square for 4 df , at 5% lvel of significance is 9.488
Since Chi square caluclated is less than chi square tabulated, fail to reject H0.
Hence Variable 1 is independent of variable 2
d) The P-Value is 0.7995
Since p value is greater than significance level. Fail to reject H0.
Hence Variable 1 is independent of variable 2
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