1. 0.5/1 points I Previous Answers OsUniPhys1 12.1.WA. 005. My Notes Ask Your T
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1. 0.5/1 points I Previous Answers OsUniPhys1 12.1.WA. 005. My Notes Ask Your T As shown in the figure below, we have a square, with one meter sides, that is free to rotate about an axis perpendicular to the plane of the square, a distance a from one side and a distance b from the other side. Two forces, F? and F2, are applied to diagonally opposite corners, and act along the sides of the square, first as shown in case () and then as shown in case (ii) of the drawing. In each case, the net torque produced by the forces is zero. If the magnitude of F2 is 8 times that of F1, find the distances a and b that locate the axis. It should be noted that a and b are not drawn to scale 0.02 a Since we need to calculate torques, see if you can write an expression for the torque in terms of the force producing the torque and the perpendicular distance between the line of action of the force = and the point about which we wish to determine he torque. A er equating the clock se to the counterclock se torques or each case and inserting the relationship between he magnitude ofthe forces, we have two equations and two unknowns (a and b). To determine the value for a, see if you can manipulate these two equations in such a manner as to eliminate b and allow you to solve for a. m 0.123 m Additional Materials eBookExplanation / Answer
1.
For case (i),
net torque = 0
F1*b - F2*a = 0
and F2 = 8F1
F1*b - 8F1*a = 0
b = 8a ......(1)
For case (ii),
net torque = 0
F1*(1 - a) - F2*b = 0
F1*(1 - a) - 8F1*b = 0
1 - a = 8b ......(2)
from eq(1) and (2),
1 - a = 8*8a
1 - a = 64a
a = 0.0153 m
b = 8*a = 8*0.0153
b = 0.123 m
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