Question 4: You are working for a biomedical manufacturing company who develops

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Question 4: You are working for a biomedical manufacturing company who develops new synthetic material for bone implants. In order to measure the strength of this new material, you would need to perform destructive testing. Due to budget constraints, the test can only be conducted 16 times. Assume the tensile strengths of the material is normally distributed, and your testing shows that the synthetic material has a mean tensile strength of 150MPa, with a standard deviation of 10 MPa. Use this information and answer questions 4a to 4c. Question 4a: In order to find a confidence interval for the true average tensile strength of this material, which distribution table would you use? Not eough information to tell C Z-table Either table will provide the same answer t-table O Question 4b: Why did you select the table in ustion 4a to find a confidence interval for the average thickness of the module made by this company? (select all that apply) The tensile strength ofthe material is normally distributed. The population standard deviation of the tensile strength of the material is known. The sample standard deviation (16 samples) ofthe tensile strength is known. The distribution ofthe tensile strength of the material is unknown. The sample size is less than 30 Question 4c: Find the lower bound of a 95% confidence interval for the average tensile strength of this new material.(Use 2 decimal places) Question 4d: You calculate that 98% confidence interval (CI) for the average tensile strength of this new material is [143.495, 156.505]. Which of the following statement gives a valid interpretation of this CI? 98% of this new material has a tensile strength that is between this CL 98% of the 16 samples have a tensile strength that is between this CL Since the true population mean is unknown, 98% of time that a confidence interval is computed the true mean will fall within the 98% CL Since the true population mean is unknown, there is a 98% probability this C, [143.495 156.505], will contain the true population mean. C

Explanation / Answer

4 a ) t - table

4 b ) The sample size is less than 30

4d ) Since the true population mean is unknown , there is a 98 % probability this CI ( 143.495 , 156.505 ) will contain the true population mean .

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