FOR FRIDAY WITH DRZ-C Use SPSS ou are interested in discovering if alcohol impai
ID: 3066663 • Letter: F
Question
FOR FRIDAY WITH DRZ-C Use SPSS ou are interested in discovering if alcohol impairs one's ability to perform a test of manual y. You randomly assign 21 subjects to one of 3 groups. Subjects in Group 1 consume a drink with 3 ounces of alcohol (the equivalent of about 3 beers), subjects in (n -9) consume a drink with 1 ounce of alcohol (equivalent to one beer), and in Group 3 consume a drink with no alcohol in it at all. After waiting 30 minutes, gects are tested on a manual dexterity task. High manual dexterity test scores indicate Conduct an ANOVA using the data in Table 11.6 to determine if alcohol has an effecet on performance. If the F-statistic is significant, conduct a post-hoc Group 2 subjects better performance. Tukey test to compare means. Describe the effect of alcohol on manual dexterity. Table 11.6 Score on manual dexterity test subje Group 1 Group 2 Group 3 ind. V. Groe1 2,3 31 42 69 56 57 67 47 62 72 65 31 31 56 48 46 39 41 47 USE SPSS 14. A human factors psychologist studied three computer keyboard designs. Three samples of individuals were given material to type on a particular keyboard, and the number of errors committed by each subject was recorded. The data are shown in Table 11.9. Does typing performance differ significantly among the three types of keyboards?Explanation / Answer
11] By using MINITAB
MTB > OneWay;
SUBC> Response 'responce';
SUBC> Categorical 'group';
SUBC> IType 0;
SUBC> Tukey 5;
SUBC> GMCI;
SUBC> TGrouping;
SUBC> GIntPlot;
SUBC> TMethod;
SUBC> TFactor;
SUBC> TANOVA;
SUBC> TSummary;
SUBC> TMeans;
SUBC> Nodefault.
One-way ANOVA: responce versus group
Method
Null hypothesis All means are equal
Alternative hypothesis At least one mean is different
Significance level ? = 0.05
Equal variances were assumed for the analysis.
Factor Information
Factor Levels Values
group 3 1, 2, 3
Analysis of Variance
Source DF Adj SS Adj MS F-Value P-Value
group 2 2121.5 1060.76 19.25 0.0001
Error 18 991.7 55.10
Total 20 3113.2
Here pvalue = 0.0001 < alpha = 0.05
Reject H0 at 5% los and the test is significant.
Tukey Pairwise Comparisons
Grouping Information Using the Tukey Method and 95% Confidence
group N Mean Grouping
3 6 65.33 A
2 9 43.78 B
1 6 42.17 B
Means that do not share a letter are significantly different.
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