(1 point) Samples were collected from two ponds in the Bahamas to compare salini
ID: 3066890 • Letter: #
Question
(1 point) Samples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site. Pond 1: 37.45, 37.54, 37.02, 37.03, 38.85, 37.01, 37.03 Pond 2: 38.24, 40.08, 39.04, 38.53, 38.71 use a 006 sgrificance level to test the cam that the two ponds have te same mean sainty value (1.) The test statistic is (2.) The conclusion is OA. There is not sufficient evidence to indicate that the two ponds have different salinity values. OB. There is sufficient evidence to indicate that the two ponds have different salinity values. (3.) We should OA. not take the results too seriously since neither sample is big enough to be meaningful. OB. remove the largest and smallest values from the larger data set and only test equal size samples. O C. check to see if the data appear close to Normal since the sum of the sample sizes is less than 15. O D. All of the above.Explanation / Answer
a)
Hypothesis:
H0 : mu1=mu2
Ha : mu1 not equal to mu2
1)
Test statistics:
x1 = 37.4186 , x2 = 38.92 , s1 = 0.6699 , s2 = 0.7102, n1 = 7, n2 = 5
t = ( x1 - x2) / sqrt(s1^2/n1 + s2^2/n2)
= (37.4186 - 38.92) /sqrt(0.6699^2/7 + 0.7102^2/5)
= -3.6963
2)
P value is calculated using t = -3.6963
with df = 10 at 0.05 significance level
P value = .00413
we reject the null hypothesis.
There is sufficient evidence to indicate that the two ponds have different salinty values
3)
Answer is option C)
we should check to see if the data appear close to normalsince the sum of the sample sizes is less than 15
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