Select the best XLSTAT printout to answer each question. Required conditions hav

Question

Select the best XLSTAT printout to answer each question. Required conditions have been met for each question. A significance level of ?? = 0.05 is used for each hypothesis test and a confidence level of 95% is used for each confidence interval estimate

Two industrial printers were each made to print 12 different manuscripts and the number of printing errors was recorded for each run. Can we infer that one printer makes more errors than the other? Printout # ___________________ ??0: ________________________ ??1: ________________________ p-value: _____________ Conclusion: Accept ??0 Reject ??0

Analysis of variance (Amount):

Source

Sum of Squares

Mean Squares

3462.363

177

15070.775

Corrected Total

180

18533.138

T-test for two independent samples/ two-tailes tests:

95% confidence interval on the difference the means: ( 0.276 , 1.191 )

Fisher’s F-Test / Two-tailes test:

ratio

1.037

F oberserved value

1.037

F Critical value

2.979

DF1

14

DF2

14

p-value (two tailed)

0.947

alpha

0.05

Type l Sum of squares analysis (Var 1 ):

Source

DF

Sum of Sqaures

Mean Squares

F

pr > f

Q1

1

11.25

11.25

1.115

0.294

Q2

2

135.85

45.283

45.283

0.006

Q1*Q2

3

6.25

2.083

0.207

0.892

T-test for two independent samples / Two-tailes test:

Difference

0.733

t(observed value)

3.322

t(critival value)

2.074

DF

22

p-value

0.003

alpha

0.05

Z-test for two proportions / two-tailed test:

95% confidence interval on the difference the means: ( -0.025, 0.105 )

Type l sum of squares analysis:

Source

DF

Sum of Sqaures

Mean Squares

F

pr > f

Q1

4

616.421

154.105

4.714

0.002

Q2

19

3574.166

188.114

5.754

< 0.0001

T-test for two paired samples / upper tailed test:

Difference

0.583

t(observed value)

1.023

t(critival value)

1.796

DF

11

p-value

0.164

alpha

0.05

Z-test for two proportions / upper-tailed test:

Difference

0.04

z(observed value)

1.2

z(critival value)

1.645

p-value

0.115

alpha

0.05

Source

Sum of Squares

Mean Squares

3462.363

177

15070.775

Corrected Total

180

18533.138

Explanation / Answer

As, the samples are independent of each other and the hypothesis can be stated as,

H0 : The mean number of printing errors recorded by printer 1 and printer 2 are equal.

H1 : The mean number of printing errors recorded by printer 1 and printer 2 are not equal.

we will be using T-test for two independent samples / Two-tailes test:

Calculated Degree of freedom = n1 + n2 - 2 = 12 + 12 - 2 = 22

DF in the output for the test is 22 which matches with the calcuated degree of freedom.

The mean difference is 0.733. p-value: 0.003 As, p-value is less than the significance level (0.05), we reject the Null hypothesis and conclude that there is significant evidence that the mean number of printing errors recorded by printer 1 and printer 2 are not equal.

So, we infer that one printer makes more errors than the other.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.