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& Take a Test Bukola Abdulwahab Omotose Mille Fe .E 1781 006 Elementary Statisti

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Question

& Take a Test Bukola Abdulwahab Omotose Mille Fe .E 1781 006 Elementary Statistic Quiz: Quiz 6 This Question: 1 pt Bukola Abdulwahab Omotose 13/25/18 7:59 PM Submit Quiz of 10 (4 complete) This Quiz: 10 pts possible Assume that human body temperatures are normally dstributed with a mean of 98 23"F and a standard deviation of 0 62F a. A hospital uses 100 6"F as the lowest temperature considered to be a lever Whas percentage of nomal and heathy persons would be considened to have a fever? Does this percentage suggest that a cutoff of 100 6'F is appropriate? b. Physicians want to select a minimum temperature for requining further medical tests. What should that temperature be, f we want only 5 0'% of heathy people to exceed t7 (Such a result is a false pesitive, meaning that the test nesult is positive, but the subject is not really sick ) a.Th* percentage of normal and healthy persons considered to have a fever ali Round to two decimal places as needed) Does this pencentage suggest that a cutoit of 100 6F is appropriate? O A. No, because there is a small probablity that a normal and healthy person would be considered to hae a teve O B. Yes, because there n a large probabity that a normal and healthy person would be considered to has a fever . C. Yes, because there is a small probablity that a normal and healthy person would be considered to have a feve O D. No, because there is a large probability that a normal and healthy person would be censidened to have a tever b. The minimum, temperature for rearing urther medical tests should b. 199 24eF e we want only 5 0% r/heithy people i Round to two decimal places ay needed) mod . Cick to select your answerts Betore you start

Explanation / Answer

mean = 98.23
sd = 0.62

a)
P(X > 100.6)
= P(z > (100.6 - 98.23)/0.62)
= P(z > 3.8226)
= 0.00007

Yes, because there is small probability that a normal and healthy person would be considered to have a fever.

b)
z-value for 95% = 1.6449

using central limit theorem,
x = mean + z*sigma
x = 98.23 + 1.6449*0.62
x = 99.2498

Minimum temperature required for further medical test should be 99.24