In a poll of 175 randomly selected U.S. adults, 89 said they favored a new propo

Question

In a poll of 175 randomly selected U.S. adults, 89 said they favored a new proposition. Based on this poll, compute a 99% confidence interval for the proportion of all U.S. adults in favor of the proposition (at the time of the poll). Then complete the table below Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) What is the lower limit of the 99% confidence interval? What is the upper limit of the 99% confidence interval?

Explanation / Answer

Answer to the question is as follows:

LCL and UCL can be calculated as:

Z = 2.575 for CI of 99%

Also, p^ = x/n = 89/175 = .5086

So, lower limit and upper limit are given for 99% CI as :
= .5086 +/- 2.575*sqrt(.5086*.4914/175)
= 0.4113 to 0.6059

LCL = .4113
UCL = .6059

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