space Suppose A, B, and C are events in the s P(A) 0.46, P(B) 0.5, P(C) 0.44, P(
ID: 3068251 • Letter: S
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space Suppose A, B, and C are events in the s P(A) 0.46, P(B) 0.5, P(C) 0.44, P(AnB) 0.35, P(AnC) 0.32, P(Bnc) 0.32, P(AnBenc)- o.25. Round your answers to 4 decimal places a. Find P(AUBUC). 0.66 s answer now shown above. You are correct. Previous Tries rec is 160-9767 b. Find P((AnB)UC) Answer Tries 0/5 c. Find P(An(Buc) Submit Answer Tries 0/5 The Starfleet Academy soccer team excels on muddy fields in the rain. The probability that the Starfleet Academy soccer team wins given that the field is muddy is 0.62. The probability that the Starfleet Academy soccer team wins given that the field is dry is 0.31 ". If the forecast for rain on game day has a 63%,chance of rain, what is the probability that the Starfleet Academy team wins? 39 Tries 2/5 Previosus.Iries b. Name the one primary result that you used (or that could be used) to solve the problem. Law of Tetal Probability 0 Axioms of Probability Central Limit Theorem Subrit Ansaer j Tries o/10Explanation / Answer
1)
a) P(A U B U C)=P(A)+(B)+P(C)-P(A n B)-P(B nC)-P(A n C)+P(A n B n C)
=0.46+0.5+0.44-0.35-0.32-0.32+0.25=0.66
b)
P((A n B) uC) =P(C)+(P(A n B)-P(An B nc))=0.44+(0.35-0.25)=0.54
c)
P(A n (B uC))=P(A n B)+P(A n C)-P(A n B n C)=0.35+0.32-0.25=0.42
2)
P(team wins)=P(wet)*P(wins|wet)+P(dry)*P(wins|dry)=0.63*0.62+(1-0.63)*0.31=0.5053
b)
law of total probability
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