b) What is the probability that a county resident had no water and no cell phone
ID: 3068574 • Letter: B
Question
b) What is the probability that a county resident had no water and no cell phone service?
c) What is the probability that a county resident was without exactly two of these?
d)what is the probability that a county resident was only without electricity?
e) what is the probability that a county resident was only without at least one of these?
1. A hurricane made landfall in a particular county in Florida. The following information was determined regarding county residents following the hurricane 50% had no electricity 47% had no water 38% had no cell phone service 10% had no water and no electricity and no cell phone service 20% did have electricity, water, and cell phone service 14% had no electricity and no cell phone service 22% had no electricity and no water 56% had no water or no cell phone service . . .Explanation / Answer
here let event A =no electricity ; B=no water and C =no cell phone service
also as P(A u B)=P(A)+P(B)-P(A n C)
b)
probability that a county resident had no water and no cell phone service =P(B n C)
=P(B)+P(C)-P(B n C)=0.47+0.38-0.56=0.29
c)probability that a county resident was without exactly two of these:
d)
probability that a county resident was only without electricity=P(A)-P(AnB)-P(AnC)+P(AnBnC)
=0.5-0.22-0.14+0.1=0.24
e)
probability that a county resident was only without at least one of these
=1-P(have all of them)=1-0.20 =0.80
P(A)= 0.5 P(B)= 0.47 P(C)= 0.38 P(AnB)= 0.22 P(BnC)= 0.29 P(AnC)= 0.14 P(AUB)= 0.75 P(BUC)= 0.56 P(AUC)= 0.74 P(AnBnC) = 0.1Related Questions
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