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1. (2 pts.) Which of the following are degrees of freedom in which energy can be

ID: 306860 • Letter: 1

Question

1. (2 pts.) Which of the following are degrees of freedom in which energy can be placed in solids? (Choose all that apply, but wrong answers will be penalized.) (a) Translational kinetic energy (d) Vibrational kinetic energy (b) Rotational kinetic energy (e) All of the above (c) Potential energy (f) None of the above. 2. (2 pts.) If an object gains 500 J of energy during a constant volume process, the change in its internal energy is (a) -500 J. (e) 0J. (b) 500 J. (d) 250 J. (e) unable to be determined (f) none of the above. 3. (2 pts.) If the volume of an ideal gas is quadrupled while its temperature is dout its the pressure (a) remains the same. (b) decreases by a factor of 2. (c) decreases by a factor of 4. (d) increases by a factor of 2. (e) increases by a factor of 4. (f) none of the above.

Explanation / Answer

1)

.There are 3 directions of vibration: namely the components x, y and z and each of these directions has two degrees of freedom; one of potential energy and one of kinetic energy. So in total there are 3×2=6 degrees of freedom.

so answer is E all the above

2)when you apply heat to system it only goes to system to add to its internal enegy since no other action is possible for this applied heat in either cases. Since all heat is now directly going to system therefore the Change in internal energy is only difference of intial temperature and final temperature of system which is same as you applied same heat energy

so answer is B 500j

3)

Write the combined gas law:
P1V1 / T1 = P2V2 / T2
I will assign a value of 1 to V1 and allow it to double. I will assign a value of 1 to T1 and allow its value to quadruple.
[(P1)(1)] / 1 = [(P2)(2)] / 4
P1 = P2 / 2
2P1 = P2
so answer is D)increase by a factor of 2