poirts 0 12.P.040 My Nodes Ask Your A piece of sssuming that the heat lost to or

Question

poirts 0 12.P.040 My Nodes Ask Your A piece of sssuming that the heat lost to or gained from the surroundings is negigible, determine the specific heat capacity of the liquid. (See m , 52.4. e. The mess of the glass end the liquid , the seme. lgnering the container that holds the glassend iquid Liquid tnat he t . mpe "ture cf 43.0 C i, poured over the guns», completely c 'er ng k, a d the temperature 't equilb u 122 for appropriate constants has ter ,erature ?f?7.6. and Add tional Matoriab u secton 12

Explanation / Answer

According to the concept of the thermal properties of the matter

M1s1(T1-T3)=M2s2(T3-T2)

But M1=M2

Given that

Temperature of the glass T1=77.6 c

Temperature of the liquid T2=43 c

Equivalent temperature T3=52.4 c

Specific heat of the glass s1=840 j/kg.c

Now we find the specific heat of the liquid

S1*(T1-T3)=s2*(T3-T2)

840*(77.6-52.4)=s2(52.4-43)

21168=9.4s2

S2=2251.9 j/kg.c

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