O 1/9 points l Previous Answers DevoreStat7 12 P 046 at. My Notes O Ask Your Tea
ID: 3069308 • Letter: O
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O 1/9 points l Previous Answers DevoreStat7 12 P 046 at. My Notes O Ask Your Teache The following information is from a report on the determination of silver content of galena crystals grown in a closed hydrothermal system over a range of temperature. With x-crystallization temperature in °C and y-Ag2S in mol%, the data follows. x 398 292 352 575 568 450 550 408 484 352493 601 601 y 0.2 0.05 0.23 0.43 0.3 0.40 0.44 0.44 0.45 0.09 0.59 0.63 0.60 From which Dr, " 6124, -3,01 5,896, -4.85, Eyi2 . 2.2331, -2473.91, b1-0.00 144, -o.307, and (a) Estimate true average silver content when temperature is 673°C using a 95% confidence interval. (Give answers accurate to 3 decimal places.) Enter a number b) Calculate a 95% CI for the true average change in silver content associated with a 1°C increase in temperature. Give answers accurate to 5 decimal places.) () Suppose it had previously been believed that when crystallization temperature was 388°C, true average silver content would be 0.25. Carry out a test at significance level 0.05 to decide whether the sample data contradicts this prior belief. Reject Ho and conclude the data contradicts the prior belief. ) Reject Ho and conclude the data does not contradict the prior belief. . Fail to reject Ho and conclude the data does not contradict the prior belief. Fail to reject Ho and conclude the data contradicts the prior belief.Explanation / Answer
The statistical software output for this problem is:
Simple linear regression results:
Dependent Variable: y
Independent Variable: x
y = -0.30713194 + 0.0014439444 x
Sample size: 13
R (correlation coefficient) = 0.80297751
R-sq = 0.64477288
Estimate of error standard deviation: 0.1169699
Parameter estimates:
Predicted values:
Hence,
a) 95% CI when x = 673:
(0.504, 0.825)
b) 95% CI for slope:
(0.00073, 0.00216)
Parameter Estimate Std. Err. DF 95% L. Limit 95% U. Limit Intercept -0.30713194 0.15564684 11 -0.64970832 0.03544443 Slope 0.0014439444 0.00032314973 11 0.00073269661 0.0021551921Related Questions
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