(10%) Problem 9: A 2 cm tall obiect is 23 cm to the left of a converging lens wi
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(10%) Problem 9: A 2 cm tall obiect is 23 cm to the left of a converging lens with a focal length of 11 cm. A second lens (a diverging lens) with a focal length of -7 cm is 28 cm to the right of the first lens * 50% Part (a) What is the position of the image (in cm)? Grade Summary Deductions Potential s'=(23 * 11)/( 11-23 ) 2% 98% Submissions Attempts remaining: 3 (2% per attempt) 789 HOME cos) cotan0 asin0 acoso atan) acotan) sinh0 cosh)tanh) cotanh0 Degrees O Radians sin tan() ? TA 45 6- detailed view 2% 0 END O BACKSPAC E CLEAR Submit I give up! Hints: 0 for a 0% deduction. Hints remaining: 0 Feedback: 2% deduction per feedback. 50% Part(b) What is the height (in cm) of the image?Explanation / Answer
a ) given
u1 = 23 cm
f1 = 11 cm
f2 = - 7 cm
1/f1 = 1/u1 + 1/v1
1/11 = 1/23 + 1/v1
v1 = 21.083 cm
hi1 = ( - v1/u1 ) ho1
= - 21.08 X 2 / 23
= - 1.833
b )
u2 = 21.08 + 28
= 49.08 cm
1/f2 = 1/u2 + 1/v2
1/-7 = 1/49.08 +1/v2
v2 = - 6.126 cm
hi2 = ( - v2/u2 ) ho2
= ( 6.126 X 23 / 49.08 )
= 2.87 cm
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