A computer consulting firm presently has bds out on three projects. LetA,-(award

Question

A computer consulting firm presently has bds out on three projects. LetA,-(awarded project '), fr i 1 2 3, and suppose that p h) 0 22 ro) 0.25 13 028 nAÐ .07 pa na PA nA2 nA3) 0.01. Use the probabilities given above to compute the following probabilities, and explain in words the meaning of each one. (Round your answers to four decimal places.) - 1. t 0.05 Explain this probabil ty in words. If the firm is awarded project 2, this is the chance they will also be awarded project 1 This is the prability that the fi is awaded either pj a prajet 7 This is the probability that the firm is awarded both project 1 and project 2. th firr is awarded project 1, this is the chace they will also he awarded projet 2 Explain this probability in words If the fm is awarded projects 2 and 3, this is the chance they will also be awarded project 1. O This is the probability that the firm is awarded at least one of the projects. 1f the firrr is mardnd project 1, this is the chance they will also be awarded projet ts ? and 3. This is the probability that the firm is awarded projects 1, 2, and 3. (c) P(A2 UA2 IA) - Explain this probability in words This is the proability that the firm is awarded prnjerts 1, 2, and3. O If the firm is awarded at least one of projects 2 and 3, this is the chance they will also be awarded project 1 1f the firm is m ardnd project 1, this is the chance thery will also be iwarded t lezs1riet tif the rther twi) projects. This is the probability that the firm 's awarded at least one of the projects. Explain this probability in words. If the fim is awarded at least two of the projects, this is the chance that they will be awarded all three projects If the firm is awarded at least one of the projects, this is the chance that they will be awarded all three projects 1 his is the probability that the firm is awarded projects l, 2, and 3 This is the probability that the firm is awarded at least one of the projects.

Explanation / Answer

a)
P(A2 | A1) = P(A1 and A2)/P(A1) = 0.07/0.22 = 0.3182
Option D

b)
P( A2 and A3 | A1) = P(A1 and A2 and A3)/P(A1) = 0.01/0.22 = 0.0455

Option C

c)
P(A2 U A3 | A1) = P(A1 and A2 U A3)/P(A1)
= P(A1 and A2 and A3)/P(A1)
= 0.01/0.22 = 0.0455

Option C

d)
P(A1 and A2 and A3 | A1 U A2 U A3)
= P(A1 and A2 and A3)/P(A1 U A2 U A3)
= 0.01/0.53
= 0.0189

Option B

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