Homework: HW 12: 6-1 Score: 0 of 1 pt 14 of 16 (8 complete) HW Score: 36.36%, 8
ID: 3070280 • Letter: H
Question
Homework: HW 12: 6-1 Score: 0 of 1 pt 14 of 16 (8 complete) HW Score: 36.36%, 8 of 22 pts Question Help Find the indicate 05 Please copy and paste data from text area below 05 Selected delimiter: Tab (Round to three Positive z Scores Standard Normal (z) Distribution: Cumulative Area from the Left .5000 . .5040 .5080 5120 .5160.5199.5239.5279.5319.5 5557 .5596.5636 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6293 .6331.6368 6406 6700 .6736.6772 5398 .5438.5478 5675 .60646103 .6443 . 6808 .6844 6517 .6179 .6217 .6554 .6591 .6915 .6950 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 .7580 .7611. .6480 6628 6664. .6985 .7019 7054 .7088 7123.7157 7224 7704 7734.7764 7794 .7823.7852 .7881.7910.7939.7967.7995.8023.8051 8289 .8315 8508 .8531 .8554 8729 87498770 8925 .8944.8962 9099 .9115 .9131 .8159 .8186. .8413 8643 8665 8849 .8869 .9032 9049.9066 .9 .8078 .8106 .8340 .8365 8577 .8599 .8790 .8810 8980 .8997 .8212 8438 .8461.8485 .8238.8 8389 .8686 .87088 8888 .8907. 9177 9207 9222 .9236 . 9251 9265 9279.9292 .9306. 9319 9332 9345 9357 9370.9 9394 .9406.9418 9463 .9474.9484 . 9495.9505 .9515 .9525 .9535.9 9591 9599.9608 .9616.9625 9554 9564.95739582 9641 9649.9656 .9664 .9 9713 .9719 9772.9 9821 9826 .9830 .9834. 9861 .9864 .9868.9871.9875.9878.9881 .9884.9887 .9 9893 9896.9898 .9901.9904 .99069909 9911 9918 .9920.9922 .9925 . 9938 9940.99419943 671 .9678.9686 . .9738 .9744 .9750 97939798 9803 9838 98429846 .9850 9693 .9699 .9726 9732.9 9756 ' 9761 .9767 778.9783 .9788 .9808.9812 .9 9927 9929.9931.9932 .9934 9945 9946.9948 9949 9936 .9952 9964 .9951 .957 .9959.9960 9961 .9962 .9963.9 9965 9966 .9967 .9968 9974 .9975 9976 .9977 9981 9982.9982 9983 9987 .9987 .9987 .9988 9990 9991.99919991.9992 .99929992 .9992 .9993 .9969 99709971 99779978.9979. 9984 .9984 .9985 9985 9988 .9989.9989 .9989.9990 9979 .9980Explanation / Answer
The given table is right tailed table
In order to find the value of z such that the shaded region to the right of the z-value is 0.05, we actually need to look for the area of 0.95 which is to the left of the z.
If we look into the table the value 0.9484 represents z=1.64 and value 0.9495 represents z=1.65
Hence the z-value = 1.64
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