$2.25 $2.41 $2.30 $2.55 $2.57 $2.65 $2.28 $2.42 $2.32 $2.59 $2.39 $2.64 $2.31 $2
ID: 3070375 • Letter: #
Question
$2.25
$2.41
$2.30
$2.55
$2.57
$2.65
$2.28
$2.42
$2.32
$2.59
$2.39
$2.64
$2.31
$2.43
$2.49
$2.60
$2.34
$2.79
$2.33
$2.45
$2.51
$2.61
$2.38
$2.59
$2.35
$2.47
$2.53
$2.63
$2.67
$2.73
$2.37
$2.48
$2.54
$2.52
$2.58
$2.56
Assume the alpha value is .05. Find the mean, standard deviation and confidence interval.
$2.25
$2.41
$2.30
$2.55
$2.57
$2.65
$2.28
$2.42
$2.32
$2.59
$2.39
$2.64
$2.31
$2.43
$2.49
$2.60
$2.34
$2.79
$2.33
$2.45
$2.51
$2.61
$2.38
$2.59
$2.35
$2.47
$2.53
$2.63
$2.67
$2.73
$2.37
$2.48
$2.54
$2.52
$2.58
$2.56
Explanation / Answer
mean=sum(x)/n=89.63/36=2.4897
sd=sqrt(sum((x-mean)2)/n)=sqrt(0.6429/36)=0.1336
here sample size n=36 ( more than 30) so we use z-value to find the confidence interval
(1-alpha)*100% confidence interval for population mean=sample mean±z(alpha/2)*sd/sqrt(n)
95% confidence interval for population mean=sample mean±z(0.05/2)*sd/sqrt(n)=
=2.4897±1.96*0.1336/sqrt(36)=2.4897±0.0436=(2.4463, 2.5333)
following information has been generated using ms-excel
n= 36 sample mean= 2.4897 sd= 0.1336 z-value margin of error lower limit upper limit 95% confidence interval 1.96 0.0436 2.4463 2.5333Related Questions
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