In a study of the effect of tobacco use on bone mineral density (BMD) in middle-

Question

In a study of the effect of tobacco use on bone mineral density (BMD) in middle-aged women, BMD of 30 pairs of twins who smoke was measured. For each pair of twins, the difference between the BMD of the twin who smokes more and the twin who smokes less was calculated (M-L). The 95% confidence interval for the true mean difference in BMD was (-3.78, 0.85). What type of study is this? O Matched Pairs O Independent Samples (S pt(s)) Submit AnswerTries 0/1 If we test Ho: "There is no difference in BMD between the twins who smoke more and the twins who smoke less" against Hai "There is a difference in BMD between the twins who smoke more and the twins who smoke less", will Ho be rejected at a -0.05 O Yes O No [5 pt(s)] Submit Answer Tries 0/1

Explanation / Answer

Solution:

What type of study is this-------------->

This is matched pairs as we study about twins.

Here we can see that Ci is , (-3.78 , 0.85 ) which include zero. That means CI support to null hypothesis that There is no difference in BMD between the twins who smoke more and the twins who smoke less.

Hence Ho not rejected at 0.05 .

Hence answer is NO.

Done

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