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Safari File Edit View History Bookmarks Window Help 4)) 50% D sun 9:35 PM Q : mathxl.com Boite yLuMath 227 Statistics section 20883 Mark Rodriguez-Abad | 9/16/18 9:35 PM MIS Homework: Section 3.3 Homework (Optional) Save 3 My Score: 0 of 6 pts 2 of 2 (0 complete) Hw Score: 0%, 0 of 8 pts | 3.3.5-T Question Help The following data represent the high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population. Complete parts (a) through (c). Quiz 60-69 70-79 1491 80-89 1549 90-99 100-109 Lecture TemperatureF) Days 307 298 Lab Acti (a) Approximate the mean and standard deviation for temperature. .OF (Round to one decimal place as needed.) : 0 StatC Mult Chapter eText Tools Enter your answer in the answer box and then click Check Answer Study Pl 4 remaining Clear All Check Answer 16

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mean=291191/3658=79.6

standard deviation=sqrt(220210.52/3658)=7.76

Temperature mid-point(m) Days(f) m*f (m-79.6)^2*f 50-59 54.5 2 109.0 1260.42 60-69 64.5 307 19801.5 70036.16 70-79 74.5 1491 111079.5 38841.77 80-89 84.5 1549 130890.5 37130.79 90-99 94.5 298 28161.0 66123.46 100-109 104.5 11 1149.5 6817.92 Total= 3658 291191.0 220210.52 mean= 79.604

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