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cheg tske a p Course MResarc G Rcsearc Rcseare Reseac G Rcer Mathwa Researc Rese

ID: 3071503 • Letter: C

Question

cheg tske a p Course MResarc G Rcsearc Rcseare Reseac G Rcer Mathwa Researc Researc control C Home https//saintleo.brightspace.com/d2l/le/content/68288/viewContent/2144274/Niew Introauction to StatISTICS MAI-ZU1-CH2 KiCKy Bess Homework: Homework 3.3 Score: 0.75 of 1 pt HW Score: 58.75%, 11.75 of Help households. The highest weight is 5 73 b, the mean of all of the weights is i 1 395 tb, and the standard deviation of the weights is s 1.432 10 of 20 (14 complete) Question 10, 3.3.8 E Question a. What is the difference between the weight of 5 73 Ib and the mean of the weights? s. Now many standard daapns is tuat eundar (ai Convert the weight of 5.73 lb to a z score d. It we consider data speods that convert to z scores between -2 and 2 to be neither significantly low nor significantly high ts the weight of 5.73 tb significant? a. The diflerence is (Type an integer or a decimal. Do not round) Enter your answer in the answer box and then click Check Answer. Clear All partaining- Activity Details You have viewed this topic

Explanation / Answer

X= 5.73lb , mean= 1.895lb and standard deviation= 1.432lb

a) The difference is 5.73-1.895= 3.835lb

b) 2.68 above the standard deviation.

c) Z= X-mu/sigma

= 5.73-1.895/1.432

= 3.835/1.432

=2.678

Since Zscore is 2.678 . It isnot between -2 and +2 and therefore 5.73lb is significantly high.

Please Note: I have done the first questions along with the subparts. Please repost rest of the questions separately. Thank you

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